A bus starting from rest moves with a uniform acceleration of 0.1 m s -2 for 2 minutes. Find (a) the speed acquired, (b) the distance travelled.

S=720m anf vf=12m/s

Explanation:

acceleration=a=0.1m/s²

time taken=t=2minutes=2×60=120seconds

vi=0m/s

vf=?

distance covered=S=?

by using second equation of motion

S=vit+1/2at²

S=0m/s×120seconds+1/2(0.1m/s²)(120s)²

S=0m/s+1/2×1440m

S=720m

and now we have to find the vf

vf=vi+at

vf=0m/s+(0.1m/s)(120s)

vf=12m/s

i hope it will help you

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