A stone is dropped from a tower of height 3600cm. Find the velocity by which it strike the ground. Find the time taken to reach the ground.

1. 26.56m/s.

2. 2.71 secs.

Explanation:

The following data were obtained from the question:

Height (h) = 3600cm

Velocity (v) =..?

Time (t) =..?

Next, we shall convert the height, 36000cm to metre (m). This is illustrated below:

100cm = 1m

Therefore, 3600cm = 3600/100 = 36 m

Therefore, the height is 36m.

1. Determination of the velocity with which the stone struck the ground. This is illustrated below:

Acceleration due to gravity (g) = 9.8m/s²

Height (h) = 36m

Velocity (v) =.?

v² = 2gh

v² = 2 x 9.8 x 36

v² = 705.6

Take the square root of both side.

v = √705.6

v = 26.56m/s

Therefore, the velocity with which the stone struck the ground is 26.56m/s.

2. Determination of the time taken for the stone to reach the ground.

Height (h) = 36m

Acceleration due to gravity (g) = 9.8m/s²

Time (t) =.?

t = √(2h/g)

t = √(2 x 36/ 9.8)

t = √(72/9.8)

t = 2.71 secs

Therefore, the time taken for the stone to reach the ground is 2.71 secs

float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it