Please Help me in this Question!!

(a) 4.4 m/s²

(b) 27 N

Explanation:

Draw a free body diagram for each block.  There are four forces on the sliding block:

Tension force T pulling to the right,

Weight force mg pulling down,

Normal force N pushing up,

and friction force Nμ pulling left.

There are two forces on the hanging block:

Tension force T pulling up,

and weight force mg pulling down.

Sum of forces on the sliding block in the +y direction:

∑F = ma

N − mg = 0

N = mg

Sum of forces on the sliding block in the +x direction:

∑F = ma

T − Nμ = ma

T − mgμ = ma

Sum of forces on the hanging block in the -y direction:

∑F = ma

mg − T = ma

T = mg − ma

(a) Substitute:

mg − ma − mgμ = ma

g − a − gμ = a

g (1 − μ) = 2a

a = g (1 − μ) / 2

Plug in values:

a = (9.8 m/s²) (1 − 0.11) / 2

a = 4.4 m/s²

(b) Substitute:

T − mgμ = mg − T

2T = mg (1 + μ)

T = mg (1 + μ) / 2

Plug in values:

T = (5.0 kg) (9.8 m/s²) (1 + 0.11) / 2

T = 27 N

true tan speed = ang vel x radius