A nichrome wire has a resistance of 5 ohm. Find the resistance of another
nichrome wire whose length is four
times and the area of cross-section is
three times of the first wire.

R = 6.67 Ohm's

Explanation:

Resistance is a property of a material that measures the opposition to the flow of current through the material. It is measured in Ohm's.

              R = (ρl) ÷ A

where; R is the resistance of the material, A is its cross sectional area, l is its length and ρ is its resistivity.

For the first nichrome wire, resistance is 5 Ohm's.

i.e            R = (ρl) ÷ A = 5 Ohm's

For the second nichrome wire, length = 4l, and area of cross section = 3A. The resistance of the second wire can be determined by;

R = (4ρl) ÷ 3A

   = {(ρl) ÷ A}

   =   × 5

R = 6.67 Ohm's

Resistance of the second nichrome wire is  6.67 Ohm's.

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

b. a lightning bug, plug of grass, and a worm