At t = 3 s, a certain particle has a speed of 10 m/s and is moving at an angle of 30∘ above the +x axis. At t = 6 s the same particle is moving at 5 m/s straight down at angle of 90∘ below the +x axis. Calculate the magnitude of its average acceleration.

the answer for apex is the lowest

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s