The cart travels the track again and now experiences a constant tangential acceleration from point A to point C. The speeds of the cart are 4.50 m/s at point A and 5.00 m/s at point C. The cart takes 4.00 s to go from point A to point C, and the cart takes 1.60 s to go from point B to point C. What is the cart's speed at point B

Vi = 4.8 m/s

Explanation:

First we need to find the magnitude of constant tangential acceleration. For that purpose we use the following formula between points A and C:

a = (Vf - Vi)/t

where,

a = constant tangential acceleration from A to C = ?

Vf = Final Velocity at C = 5 m/s

Vi = Initial Velocity at A = 4.5 m/s

t = time taken to move from A to C = 4 s

Therefore,

a = (5 m/s - 4.5 m/s)/4 s

a = 0.125 m/s²

Now, applying the same equation between points B and C:

a = (Vf - Vi)/t

where,

a = constant tangential acceleration from A to B = 0.125 m/s²

Vf = Final Velocity at C = 5 m/s

Vi = Initial Velocity at B = ?

t = time taken to move from B to C = 1.6 s

Therefore,

0.125 m/s² = (5 m/s - Vi)/1.6 s

Vi = 5 m/s - (0.125 m/s²)(1.6 s)

Vi = 4.8 m/s

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

heat the gas and measure the pressure