A block of mass M is suspended from a ceiling by a spring with spring stiffness constant k. A penny of mass m is placed on top of the block. What is the maximum amplitude of oscillations that will allow the penny to just stay on top of the block

Explanation:

Given that:

Mass of block M

Mass of penny m

spring stiffness constant k

The frequency of oscillation of the block

The angular velocity is

when the penny is resting on the block

The acceleration of the penny = acceleration of the block

If R is the reaction of the block on the penny

The penny will leave the block if R = 0

Therefore the amplitude for the penny to remain on the block

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down