A golfer is teeing off on a 130.0 m long par 3 hole. The ball leaves with a velocity of 35.0 m/s at 35.0° to the horizontal. Assuming that she hits the ball on a direct path to the hole, how far from the hole will the ball land (no bounces or rolls)?

The ball will land 12.5m before that hole.

Explanation:

The motion of the golf ball can be considered as a projectile motion, where first its height is 0, then it keeps increasing to a maximum point, after which its height starts decreasing again and hits the ground (height becomes 0 again).

We need to calculate the Range (horizontal distance) of the ball which is given as:

Where

v(i) = initial velocity = 35 m/s

θ = Initial angle = 35°

g = gravitational acceleration = 9.8 m/s

Substitute in the given formula to find Range:

Distance between the hole and position where ball lands = 130m - 117.5m = 12.5m

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.

i think its c if i'm wrong