An empty parallel plate capacitor is connected between the terminals of a 10.1-V battery and charges up. The capacitor is then disconnected from the battery, and the spacing between the capacitor plates is doubled. As a result of this change, what is the new voltage between the plates of the capacitor

V' = 20.2 V

Explanation:

The formula for the capacitance of a parallel plate capacitor, with air as a medium between the plates, is given by the following formula:

C = A∈₀/d

where,

V = Capacitance of capacitor

A = Area of plate

∈₀ = permittivity pf free space

d = distance between plates

Keeping all the other variables constant, the relationship between capacitance and the distance between plates is given as:

C α 1/d

Therefore, when the distance between plates is doubled, it implies that the capacitance of the capacitor becomes half. That is:

C' = C/2

Now the formula for capacitance of a capacitor, is also given as:

Q = CV

C = Q/V

where,

Q = charge stored in capacitor

V = Voltage across capacitor

Keeping the charge constant the relationship between capacitance and voltage is:

C α 1/V

Therefore, when the capacitance is halved, the voltage must be doubled, keeping the charge constant:

V' = 2V = (2)(10.1 V)

V' = 20.2 V

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.