How much work did the movers do (horizontally) pushing a 160-kg crate 10.3 m across a rough floor without acceleration, if the effective coefficient of friction was 0.50?

The work done is 8075.2 J.

Explanation:

Given that,

Mass of crate = 160 kg

Distance = 10.3 m

coefficient of friction = 0.50

We need to calculate the normal force

Using balance equation

Here, acceleration a = 0

Put the value into the formula

We need to calculate the frictional force

Using balance equation

We need to calculate the work done

Using formula of work done

Hence, The work done is 8075.2 J.

they should be similar or the same

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.