Una pelota rueda por una pendiente con aceleración constante. Cuando pasa por un punto P su velocidad es 1,2 ms-1 y al cabo de un breve periodo de tiempo pasa por el punto Q con una velocidad de 2,6 ms-1 . a. Determine ¿cuál es la velocidad media entre P y Q?
b. Si tarda 1,4s en ir de P a Q, calcule ¿cuál es la distancia PQ?
c. Determine ¿cuál es la aceleración de la pelota entre P y Q?
d. Explicar si la aceleración media en el tramo P y Q es la misma que la calculada en la pregunta c

a) v_{m} = 1.9 m / s , b) x = 2.66 m, c) a = 1 m / s , d)the acceleration is constant the average and instantaneous acceleration is equal

Explanation:

a) The average speed is defined as the average value of the speed in a given interval

        = (v1 + v2) / 2

        v_{m} = (1,2 + 2,6) / 2

         v_{m} = 1.9 m / s

b) the distance traveled can be obtained with the average speed

       a = v_{m}  t

       x = 1.9 1.4

       x = 2.66 m

c) to find the acceleration let's use

      v = v₀ + a t

      a = (v- v₀) / t

       a = (2.6 - 1.2) / 1.4

      a = 1 m / s

d) as in the problem they indicate that the acceleration is constant the average and instantaneous acceleration is equal in the case of acceleration variables may not be the same

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