An aluminium bar 600mm long with diameter 40mm has a hole drilled in the centre of the bar. The hole is 3omm in diameter and is 100mm long. If the modulus of elasticity for the aluminium is 85GN/m^2. Calculate the total contraction on the bar due to a compresive load of 180kn

Given that,

Length of bar = 600 mm

Diameter of bar = 40 mm

Diameter of hole = 30 mm

Length of hole = 100 mm

Modulus of elasticity = 85 GN/m²

Load = 180 kN

We need to calculate the area of cross section without hole

Using formula of area

Put the value into the formula

We need to calculate the area of cross section with hole

Using formula of area

Put the value into the formula

We need to calculate the total contraction on the bar

Using formula of total contraction

Total contraction = contraction in bar without hole part + contraction in bar with hole part

Where, F = load

L = length

A = area of cross section

E = modulus of elasticity

Put the value into the formula

Hence, The total contraction on the bar is 1.227 mm²

im sorry i dont know

c) power lifting, will be your answer.

,

deku ❤