A projectile is launched with an initial velocity of 25 m/s at an angle of 30° above the horizontal. The projectile reaches maximum height at point p then falls to point a, which is 65 m below the cliff. What is the horizontal distance that it travels (labeled x in the diagram)
Answers: 2
= 25 m/s* sin(30°)= 12.5 m/s
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A projectile is launched with an initial velocity of 25 m/s at an angle of 30° above the horizontal....
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