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Physics, 18.06.2020 00:57 ibarral37102

A constant electric field with magnitude 1.50 βœ• 103 N/C is pointing in the positive x-direction. An electron is fired from x = βˆ’0.0200 m in the same direction as the electric field. The electron's speed has fallen by half when it reaches x = 0.150 m, a change in potential energy of 4.08 βœ• 10βˆ’17 J. The electron continues to x = βˆ’0.200 m within the constant electric field. If there's a change in potential energy of βˆ’8.40 βœ• 10βˆ’17 J as it goes from x = 0.150 m to x = βˆ’0.200 m, find the electron's speed (in m/s) at x = βˆ’0.200 m. Hint

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A constant electric field with magnitude 1.50 βœ• 103 N/C is pointing in the positive x-direction. An...
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