A 2.20 mH toroidal solenoid has an average radius of 7.00 cm and a cross-sectional area of 2.80 cm2 . You may want to review (Pages 994 - 997) . For related problem solving tips and strategies, you may want to view a Video Tutor Solution of
Calculating self-inductance.
A. How many coils does it have? In calculating the flux, assume that B is uniform across a cross section, neglect the varation of B with a distance from the toroidal axis. B. At what rate must the current through it change so that a potential difference of 2.80 V is developed across its ends?enter the magnitude of the rate.
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Physics, 21.06.2019 14:50
Ingrid wrote the hypothesis below. if the temperature of a liquid increases, the density of the liquid decreases because the particles move farther apart. what are the variables in her hypothesis?
Answers: 3
Physics, 21.06.2019 17:10
An object is moving east, and it’s velocity changes from 65m/s to 25m/s in 10 seconds. which describes the acceleration?
Answers: 1
Physics, 21.06.2019 23:00
The roller coaster from problem #1 then tops a second hill at 15.0 m/s, how high is the second hill? 91.5 m 79.2 m 80.0 m 68.5 m
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Physics, 22.06.2019 12:10
Consider a one meter long horizontal pipe with a constant 100 cm^2 cross sectional area. water flows rightward into the pipe at x = 0 with flow velocity 02m/sec at every point within the pipe intake area. at x=1, the rightward flow rate is 0.192 m/sec. assume the water is a conserved quantity in the pipe, so there must be a leak (a sink) somewhere in the pipe. 1. compute net volumetric flow of the source if the system to be in equilibrium. 2. now assume the pipe in the problem has no leaks. compute the net volumetric rate of change for the system.
Answers: 3
A 2.20 mH toroidal solenoid has an average radius of 7.00 cm and a cross-sectional area of 2.80 cm2...
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