A ball is kicked horizontally with a speed of 5.0 ms-1 from the roof of a house 3 m high. When will the ball hit the ground?

the time taken for the ball to hit the ground is 0.424 s

Explanation:

Given;

velocity of the ball, u = 5 m/s

height of the house which the ball was kicked, h = 3m

Apply kinematic equation;

h = ut + ¹/₂gt²

where;

h is height above ground

u is velocity

g is acceleration due to gravity

t is the time taken for the ball to hit the ground

Substitute the given values and solve for t

3 = 5t + ¹/₂(9.8)t²

3 = 5t + 4.9t²

4.9t² + 5t -3 = 0

a = 4.9, b = 5, c = -3

Solve for t using formula method

f=ma newton

f=100x2.5=250n

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach