Un tubo metálico tiene 100 metros de longitud cuando está a 0 oC y 100,13 metros cuando se calienta hasta 100 oC. ¿Cuál es el coeficiente de dilatación del material?

 α= 1.3 10-5 ºC⁻¹

Explanation:

La dilatación termica de los cuerpos esta dada por la relación  

      ΔL = L₀ α ( T -T₀)

en este caso nos piden el coeficiente de dilatación térmica

     α =DL/L₀ DT

calculemos

      α = (  100,13 -100)/[100 (100 – 0)]

       α = 1,3 10-5 ºC⁻¹

Traduction

The thermal expansion of bodies is given by the relationship

       ΔL = L₀ α (T -T₀)

in this case they ask us for the coefficient of thermal expansion

        α = ΔL / L₀ ΔT

    let's calculate

        α = (100,13 -100) / [100 (100 - 0)]

        α= 1.3 10-5 ºC⁻¹

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