Show that the surface area of the cone = √2 + 2, > 0, over the circular region
2 + 2 ≤ 2
i...
Physics, 04.06.2020 20:01 jordantay208
Show that the surface area of the cone = √2 + 2, > 0, over the circular region
2 + 2 ≤ 2
in the -plane (shown in the figure below) is 2√2 + 1
Answers: 1
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