Two cars accelerate uniformly at the same rate. The second travels for twice the time of the first. The distance covered by the second car is …………times that of the
distance covered by the first car. Justify your answer?

Double of the first car

Explanation:

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft