En un proceso isobárico, la presión del gas es de 105 Pa. Halle el desplazamiento del pistón, cuya área es de 0,4 m2, cuando el gas desarrolla un trabajo de 8 x 104 J

The displacement of the piston is 1904.76 m

Explanation:

Here we have an isobaric or constant pressure process, therefore;

Work done, W = P × (V₂ - V₁)

Where:

W = 8 × 10⁴ J

P = Pressure of the gas = 105 Pa

V₁ = Initial volume of the cylinder of the piston

V₂ = Final volume of the cylinder of the piston

We note that volume of the cylinder of the piston = Base area, A × h

Therefore;

V₁ = A × h₁

V₂ = A × h₂

Which gives;

V₂ - V₁ = A × h₂ - A × h₁ = A×(h₂ - h₁)

Where:

A = Base area of the piston = 0.4 m²

h₂ - h₁ = Displacement of the piston

∴ 8 × 10⁴ J = 105 Pa × (V₂ - V₁) = 105 Pa × 0.4 m² × (h₂ - h₁)

h₂ - h₁ = (8 × 10⁴ J)/(105 Pa × 0.4 m²)

h₂ - h₁ = 1904.76 m

Hence the displacement of the piston = 1904.76 m.

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explanation:

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5