The instantaneous speed of a particle moving along one straight line is v(t) = ate−6t, where the speed v is measured in meters per second, the time t is measured in seconds, and the magnitude of the constant a is measured in meters per second squared. What is its maximum speed, expressed as a multiple of a? (Do not include units in your answer.)

v_max = (1/6)e^-1 a

Explanation:

You have the following equation for the instantaneous speed of a particle:

  (1)

To find the expression for the maximum speed in terms of the acceleration "a", you first derivative v(t) respect to time t:

 (2)

where you have use the derivative of a product.

Next, you equal the expression (2) to zero in order to calculate t:

For t = 1/6 you obtain the maximum speed.

Then, you replace that value of t in the expression (1):

hence, the maximum speed is v_max = ((1/6)e^-1)a

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.