Physics questions regarding circuits and electricity.

A. 1.5A.

B. 3V

C. 4.5V

D. 1.5V

E. 9V

Explanation:

A. Determination of the current in the circuit.

We'll begin by calculating the total resistance. This is illustrated below:

R1 = 2Ω

R2 = 3Ω

R3 = 1Ω

Total resistance (RT) =..?

RT = R1 + R2 + R3

RT = 2 + 3 + 1

RT = 6Ω

Therefore, the total resistance is 6Ω.

Now, we can obtain the current in the circuit as follow:

Voltage(V) = 9V

Total Resistance (R) = 6Ω

Current (I) =..?

V = IR

I = V /R

I = 9/6

I = 1.5A

Therefore, the current in the circuit is

B. Determination of the voltage across 2Ω resistor.

Resistor (R) = 2Ω

Current (I) = 1.5A

Voltage (V) =..?

V = IR

V = 1.5 x 2

V = 3V.

Therefore, the voltage across 2Ω resistor is 3V.

C. Determination of the voltage across 3Ω resistor.

Resistor (R) = 3Ω

Current (I) = 1.5A

Voltage (V) =..?

V = IR

V = 1.5 x 3

V = 4.5V.

Therefore, the voltage across 3Ω resistor is 4.5V.

D. Determination of the voltage across 1Ω resistor.

Resistor (R) = 1Ω

Current (I) = 1.5A

Voltage (V) =..?

V = IR

V = 1.5 x 1

V = 1.5V.

Therefore, the voltage across Ω resistor is 1.5V.

E. Determination of the sum of the voltage across all three resistor.

Voltage across 2Ω (V1) = 3V

Voltage across 3Ω (V2) = 4.5V

Voltage across 1 (V3) = 1.5V

Total voltage (VT) =..?

VT = V1 + V2 + V3

VT = 3 + 4.5 + 1.5

VT = 9V

Therefore, the sum of the voltage across all three resistor is 9V.

i don't understand. explain it clearly

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.