Dogs keep themselves cool by panting, rapidly breathing air in and out. Panting results in evaporation from moist tissues of the airway and lungs, which cools the animal. Measurements show that, on a 35∘C day with a relative humidity of 50%, a 12 kg dog loses 1.0 g of water per minute if it is panting vigorously. What rate of heat loss, in watts, does this achieve?

Explanation:

Evaporation results in cooling because water absorbs heat equal to mass times latent heat of evaporation to get converted into vapor .

latent heat of evaporation of water = 2260 x 10³ J / kg or 2260 J / g

in the evaporation of 1 g of water , heat lost = 2260 J

heat lost per minute = 2260 J

heat lost per second = 2260 / 60

= 37.66 J /s

= 37.66 W

So heat lost by dog in watt = 37.66 W.

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

answer(20) psi;