A diver running 2.6 m/s dives out horizontally from the edge of a vertical cliff and 2.6 s later reaches the water below.
How high was the cliff?
How far from its base did the diver hit the water?

Explanation:

A diver running 2.6 m/s dives out horizontally from the edge of a vertical cliff and 2.6 s later reaches the water below.

(a) It means in horizontal direction,

Initial velocity is 0 and acceleration is g. Let h is the height of the cliff. Using equation of motion as :

(b) In horizontal direction,

Initial velocity of the driver is 2.6 m/s and acceleration is equal to 0. Let x is the distance from its base did the diver hit the water.

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explanation:

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