A converging lens with a focal length of 10 cm produces a 3-cm high virtual image of a 1-cm high object. Calculate the distance of the image from the lens. help

MRCORRECT has answered the question

Explanation:

1/u+1/v=1/f.

where.

u is the object distance.

v is the image distance.

f is the focal length of the lens

U can use this formula for the answer

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west