A square conducting plate 51.0 cm on a side and with no net charge is placed in a region, where there is a uniform electric field of 81.0 kN/C directed to the right and perpendicular to the plate. (a) Find the charge density (in nC/m2) on the surface of the right face of the plate. -716850 nC/m2 (b) Find the charge density (in nC/m2) on the surface of the left face of the plate. 716850 nC/m2 (c) Find the magnitude (in nC) of the charge on either face of the plate. nC

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft