How much work is done on a proton to move from the negative plate to a positive plate 4.3 cm away if the field is 125 N/C?

Explanation:required formula is

F=qE

F=force applied on the proton

q=charge of a proton

E=electric field

again

W=F*S

s=4.3cm

please feel free to ask any questions

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.