A 200.0 g china serving bowl is warmed 65.0°C when it absorbs 2.6 kcal of heat from a

serving of hot food. What is the specific heat of the china dish?

837.2 J/kg.oC

Explanation:

Mass of China dish, m = 200g

Change in temperature, ΔT = 65.0°C

The heat energy, Q = 2.6 kcal = 2600 cal

The relation between the heat flow and specific heat is given as:

Q = mcΔT

Therefore, the specific heat of the China dish is:

c = Q/mΔT = (2600cal)/(200g)(65.0°C) = 0.2 cal/g.°C

Note:

1 cal = 4.186 J

1 g = 10^-3 kg

Therefore, week have:

c = (0.2)(4.186/10^-3) J/kg.oC

= 837.2 J/kg.oC

i wanna say it’s between b and d, leaning more towards b.

it about 600 mph from what i calculated