Consider a silver wire with a radius of 4.0 x 10^-3 meter. determine the cross sectional area of this wire

5.024×10⁻⁵ m

Explanation:

A = πr² Equation 1

Where A = cross sectional area of the wire, r = radius of the wire, π = pie.

Given: r = 4.0×10⁻³ meter.

Constant: π = 3.14.

Substitute these values into equation 1

A = 3.14(4.0×10⁻³)²

A = 3.14×16×10⁻⁶

A = 50.24×10⁻⁶

A = 5.024×10⁻⁵ m.

Hence the cross sectional area of the wire = 5.024×10⁻⁵ m

the electric field is a “force field” around a charged object that illustrates the direction the electric force would push an imaginary 

their crystal patterns have been disrupted by stress