Un acróbata de masa M, se impulsa hacia arriba con una velocidad v0 desde un

trampolín. Mientras sube, a una altura h sobre el trampolín, recoge a un mono entrenado de masa m. ¿Cuál es la altura máxima que alcanzan el mono y el acróbata?

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

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