A+block+of+1.2kg+is+placed+on+an+in cluded+plane+at+60°+to+the+horizont al.+Calculate.+a. The+force+that+will+make+the+block+ to+slide+down+the+plane. B.The+coefficient+of+friction+.C.+T he+normal+reaction+d.+The+friction+ force

a. 10.2 N b. 1.73 c. 58.8 N d. 10.2 N

Explanation:

a. The force that will make the block slide down the plane

This is the component of the block's weight along the plane F = mgsinθ where m = mass of block = 1.2 kg, g = 9.8 m/s² and θ = angle of incline = 60°.

So, F = mgsinθ = 1.2 kg × 9.8  m/s² × sin60°.= 10.18 N ≅ 10.2 N

b. The coefficient of friction

The coefficient of friction, μ = tanθ = tan60° = 1.73

c. The normal reaction.

This is equal to the vertical component of the block's weight. So, F = mgcosθ. Substituting the values for the variables from above, we have

F = mgcosθ = 1.2 kg × 9.8  m/s² × cos60°.= 58.8 N

d. The frictional force

Since the block does not slide, there is no net force on it. If f is the frictional force, then

F - f = ma. Since a = acceleration = 0,

F - f = 0

f = F = mgsinθ = 1.2 kg × 9.8  m/s² × sin60°.= 10.18 N ≅ 10.2 N

causes

fossil fuels burn

cities become more industrialized

human population grows worldwide

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach