A box having a weight of 8 lb is attached to a massless rod with length 2 feet. The initial speed of the box is 5 ft/s. Neglect friction and size of the box. If a moment of 10 ft-lb causes the box to increase its velocity from 5 ft/s to 10 ft/s, determine: rictly no di without written permissTON. a) The time it takes for the box to go from 5 ft/s to 10 ft/s b) The total work done during the time that the box goes from 5 ft/s to 10 ft/s c) The tension in the rod when the box has reached 10 ft/s

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

pecialized keyboards

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000