Two objects, A and B, are brought into contact with each other. The initial temperature of object B is 430 K. The heat capacity of object A is a constant 3 J/K and the heat capacity of object B is a constant 2 J/K. Through the exchange of heat the two objects eventually obtain a common final temperature of 340 K.

1. The initial temperature of object A was K.
2. The amount of heat exchanged during the process of obtaining the final temperature was J.
3. The final temperature would be (higher, lower, stay the same), if the heat capacity of object B was higher and the other given parameters remain constant .

1) 136.67 K

2) 1016.66 Joules of energy per unit mass

3) lesser

Explanation:

Detailed explanation and calculation is shown in the image below

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

0.55x745.7j and a calculator