A person uses 25.0 J of kinetic energy to push an object for 11.0 How are work and power affected if the person uses the same amount of kinetic energy to push the object in less time ?

Complete question:

A person uses 25.0 J of kinetic energy to push an object for 11.0 s How are work and power affected if the person uses the same amount of kinetic energy to push the object in less time ?

The power will increase, and the amount of work will remain the same

Explanation:

Given;

Kinetic energy, K = 25.0 J

time of work, t = 11.0 s

Power = work / time = Energy / time

This equation shows that power is inversely proportional to time

Also, Energy is directly proportional to work (both are measured in Joules)

Since the person will use the same amount of kinetic energy to push the object in less time.

It means that energy will be constant (work done will not change) and the time will be reduced.

Power and time are inversely proportional, decrease in time means increase in power.

Thus, the power will increase, and the amount of work will remain the same

since you're a real machine, your ama is always less than your ima, because you can never totally eliminate friction.

0.55x745.7j and a calculator