A thin, circular disk of radius R = 30 cm is oriented in the yz-plane with its center as the origin. The disk carries a total charge Q = +3 μC distributed uniformly over its surface. Calculate the magnitude of the electric field due to the disk at the point x = 15 cm along the x-axis.

electric field due to the disk at the point x = 15 cm along the x-axis is;

E = 3.31 x 10^(9) N/C

Explanation:

We are given;

Radius;r = 30cm = 0.3m

Charge; Q = +3 μC = +3 x 10^(-6) C

Point, x = 15 cm = 0.15m

The formula for electric field due to the disk on the x-axis is given by;

E = [Q/(2ε₀•π•r²)] * [1 - (x/√(x² + r²))]

Where;

Q, x and r are as stated earlier

ε₀ is the permittivity of free space and has a constant value of 8.85 x 10⁻¹² C²/N.m

Thus, plugging in the relevant values, we have;

E = [3 x 10^(-6)/(8.85 x 10⁻¹² x π x 0.3²)] * [1 - (0.15/√(0.15² + 0.3²))]

E = 3.31 x 10^(9) N/C

not too sure thinking it will always be directed towards the centre of the earth. could be wrong not sure

what question you dont ask a question

explanation: