Physics, 19.10.2019 17:30 xxtonixwilsonxx

Which statements about acceleration are true? check all that apply. a. the si units of acceleration are m/s2. b. for acceleration, you must have a number, a unit, and a direction. c. to calculate acceleration, divide the change in speed by the change in time. d. the symbol for acceleration is .

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Answer from: noeminm105

The first thing you should know is that acceleration is a vector, therefore, it has magnitude, and direction.

By definition, we have that the vector acceleration is given by:

$a = \frac{dv}{dt}\\$

Where,

dv/dt: derived from the velocity vector with respect to time,

Therefore, the units of the vector acceleration are:

$a = \frac{\frac{m}{s}}{s}\\$

$a = \frac{m}{s^2}$

The symbol of acceleration is:

$a^{-}$

The statements about acceleration that are true are:

a. the si units of acceleration are m/s2.

b. for acceleration, you must have a number, a unit, and a direction.

d. the symbol for acceleration is (True, only if the symbol is the same as above)

Which statements about acceleration are true? check all that apply. a. the si units of acceleration

Answer from: pedroramirezr2

A is True:

The formula for acceleration is:

$Acceleration = \frac{Vf-Vi}{t}$
$Acceleration = \frac{Xm/s-Xm/s}{s} = Xm/s^{2}$

Because the unit of velocity is m/s and the unit of time is second this is what happened:

$\frac{m}{s}$ ÷ $\frac{s}{1}$

$\frac{m}{s}$ ÷X $\frac{1}{s}$ = $\frac{m}{s^{2}}$

B is True:

Acceleration is a vector quantity, so that means it should have both magnitude and direction. When given an acceleration, the sign usually indicates the direction. A negative value is a sign that it is decelerating and not accelerating.

D could be true only if:

Your question is actually broken so we do not know the symbol you are showing. But in general, the symbol of acceleration is a letter "a" with an arrow on top. You can see in the picture attached to see the symbol I am referring to.

C is not true because acceleration is the change in VELOCITY over time. Velocity and speed are different.

Answer from: Quest

we need to know the time interval during which the force acts. impulse of force = momentum change

Answer from: Quest

Answerthe force between the charges will be f/9 (one-ninth of force f)explanationcoulomb's law relates the magnitudes two point charges q₁ and q₂, the distance, r, between the charges, and the electrostatic force, f, between the two charges: $f = \dfrac{k q_1 q_2}{r^2}$ k represents coulomb's constant, k = 8.99×10⁹ n·m²/c².note that if we have r = 3r, then $\begin{aligned} f & = \dfrac{k q_1 q_2}{r^2} \\ f_{3r} & = \dfrac{k q_1 q_2}{(3r)^2} \\ & = \dfrac{k q_1 q_2}{3^2 \cdot r^2} \\ & = \frac{1}{9} \cdot \boxed{\dfrac{k q_1 q_2}{r^2} } \\ & = \frac{1}{9} f & & \left(\text{\footnotesize since $ f = \tfrac{k q_1 q_2}{r^2}$}\right) \end{aligned}$

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Which statements about acceleration are true? check all that apply. a. the si units of acceleration...

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