A candle is placed 9 cm in front of a concave mirror with a focal length of 6 cm. How far from the mirror will the image be located?What is the magnification of this image?
Show your work

Explanation:

Given that,

An object is place 9cm in from of a concave mirror

Then, object distance is 9cm

u = 9cm

Focal length of the mirror is 6cm

Then, f = 6cm

A. We want to find image distance

Image distance v?

From mirror formula

1 / f = 1 / u + 1 / v

Where

f is focal length

u is object distance

v is image distance

1 / f = 1 / u + 1 / v

1 / 6 = 1 / 9 + 1 / v

1 / v = 1 / 6 - 1 / 9

1 / v = 1 / 18

Take reciprocal of both sides

v = 18 cm

Since the image distance is positive, then, the image is real.

B. Magnification M?

Magnification can be determined using

M = image distance / object distance

M = v / u

M = 18 / 9

M = 2

So, the image is double.

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia