LC Circuits: A series circuit contains an 80-μF capacitor, a 0.020-H inductor, and a switch. The resistance of the circuit is negligible. Initially, the switch is open, the capacitor voltage is 50 V, and the current in the inductor is zero. At time t = 0 s, the switch is closed. When the potential across the capacitor is 30 V, what is the rate of change of the current?

The rate of current change in the circuit is

Explanation:

From the question we are told that

     The capacitor has a value

     The inductor has a value

     The capacitors voltage is   at t = 0s

     The new capacitor voltage is

Generally when the switch is  closed the potential across the inductor is equal to the potential across the capacitor

So for the inductor

     rate of current change is given as

Where is the  voltage across the inductor.    

Substituting value

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