A bungee jumper with a weight of 600 N dives off a tower. When he reaches the point where the elasticity of the bungee cord makes him spring back up, the bungee cord has increased its length by 10 m. What is the Hooke's constant for the bungee cord?

60N/m

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Force (F) = 600 N

Extention (e) = 10m

Hooke's constant (K) =..?

Step 2:

Determination of the Hooke's constant.

From Hooke's law,

F = Ke

K = F/e

K = 600N/10m

K = 60N/m

Therefore, the Hooke's constant for bungee cord is 60N/m

1 - wave length

2 - amplitude

3 - crest

4 - trough

explanation:

duh.

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