Physics, 05.05.2020 16:22 ChaseRussell24

. A lightbulb with a resistance of 2.9 ohms is operated using a 1.5-volt battery. At what rate is
electrical energy transformed in the lightbulb?

Answers: 1

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Answers

Answer from: roseemariehunter12

Explanation:

Given that,

A light bulb has a resistance of 2.9ohms

R = 2.9 ohms

And a battery of 1.5V is applied

V = 1.5 V

We want to find the rate of energy transformed

First we need to know what rate of energy is

Rate of energy implies that we want to find power. Power is the rate at which work is done

P = Workdone / time

Then,

In electronic, the power dissipated by a resistor is given as

P = V² / R

P = 1.5² / 2.9

P = 0.7759 W

P ≈ 0.776 W

So, the rate at which electrical energy transformed in the lightbulb is 0.776 Watts

Answer from: KaleahV

The rate of electrical energy transformed in the light bulb is 0.78 Joules per seconds.

Explanation:

Electrical energy is given by,

E = IVt

The rate of electrical energy transformed in the light bulb can be determined by;

$\frac{E}{t}$ = IV

From Ohms law which states that the amount of current passing through a metallic conductor, e.g wire, is directly proportional to the potential difference across its ends, provided that the temperature is constant.

i.e V = IR

where: V is the potential difference, I is the current and R is the resistance of the conductor

So that: R = 2.9 Ohms and V = 1.5 Volt, find I.

⇒ I = $\frac{V}{R}$

= $\frac{1.5}{2.9}$

= 0.5172

I = 0.52 A

Then;

$\frac{E}{t}$ = IV

= 0.52 × 1.5

= 0.78 J/s

The rate of electrical energy transformed in the light bulb is 0.78 Joules per seconds.

Answer from: Quest

The answer is water molecules are split.cellular respiration and photosynthesis are complement reactions to each other. these are reverse reactions. in cellular respiration glucose and oxygen yield water and carbon dioxide. so, when respiration begins, glucose molecules are split. in the opposite reaction - in photosynthesis, carbon dioxide and water yield glucose and oxygen. thus, when respiration begins, water molecules are split.

Answer from: Quest

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge, $v = \dfrac{e_p}{q}$ then the following gives us the potential difference, $\delta v = v_b - v_a$ $\begin{aligned} \delta v & = \dfrac{e_p_b}{q} - \dfrac{e_p_a}{q} \\ & = \dfrac{\delta e_p}{q} \end{aligned}$ the formula $\delta v = \delta e_p / q$ may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get $\delta e_p = q\delta v$ using q = 8.00 × 10⁻¹⁹ c and δv = 2.00 v, we get $\begin{aligned} \delta e_p & = (8.00\times10^{-19} \text{ c})(2.00\text{ v}) \\ & = 1.60\times 10^{-18}\text{ j} \end{aligned}$ the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

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. A lightbulb with a resistance of 2.9 ohms is operated using a 1.5-volt battery. At what rate is

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