A scientist notices that an oil slick floating on water when viewed from above has many different colors reflecting off the surface, making it look rainbow-like (an effect known as iridescence). She aims a spectrometer at a particular spot and measures the wavelength to be 750 nm (in air). The index of refraction of water is 1.33.

(a) The index of refraction of the oil is 1.20. What is the minimum thickness t of the oil slick at that spot?

(b) Suppose the oil had an index of refraction of 1.50. What would the minimum thickness t be now?

The correct answer is (a) 312.5nm and (b) 125nm

Explanation:

The first step to take is to find The minimum thickness of the slick of the oil

Given that,

(a) tmin  λ/2n

We substitute 750nm ( in air) for λ and 1.20 for n for the expression of  minimum thickness t of the oil slick at that spot

thus,

tmin = (750nm)/2(1.2) = 312.5nm

The minimum thickness of the oil slick at that spot is =312.5nm

(B) we find the minimum thickness t

The minimum thickness of the oil slick at the spot will be calculated by,

tmin = λ/4n

we then 750nm ( in air) for λ and 1.50 for n  in the expression for the minimum thickness of the slick of the oil.

tmin = (750nm)/4 (1.5) = 125nm

Therefore the minimum thickness t will now be = 125nm

4

explanation:

4

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2