Physics, 06.05.2020 00:06 Aysha1311

Suppose that a wave forms in shallow water. Then the depth d of the water (in meters) and the velocity v of the wave (in meters per second) are related by the equation =v9.8d. If a wave formed in shallow water has a velocity of 5.2 meters per second, what is the water's depth? Carry your intermediate computations to at least four decimal places, and round your answer to the nearest tenth.

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Answer from: SMURFETTE86

The clear question is;

Suppose that a wave forms in shallow water. Then the depth d of the water (in meters) and the velocity v of the wave (in meters per second) are related by the equation v=√9.8d . If the wave formed in shallow water has a velocity of 5.2 meters per second, what is the water’s depth? Carry your intermediate computation to at least four decimal places, and round your answer to the nearest tenth

Water's depth;d ≈ 2.8 m

Explanation:

We are told that the relationship between the velocity and depth of the water is given by;

v = √9.8d

Where;

v is the velocity of the wave and d is the depth of the water

Now, we are given velocity; v = 5.2 m/s.

Thus, plugging it into the relation above, we have;

5.2 = √9.8d

Let's take the square of both sudes to get;

5.2² = 9.8d

27.04 = 9.8d

Let's divide both sides by 9.8 to get;

9.8d/9.8 = 27.04/9.8

d = 2.7592m

We are told to approximate to nearest tenth.

Thus, d ≈ 2.8 m

Answer from: Quest

Sound energy is produced when an object vibrates. examples are 1- a balloon popping2-a whistle3- a waterfall

Answer from: Quest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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Suppose that a wave forms in shallow water. Then the depth d of the water (in meters) and the veloci...

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