If the torque is counteracted by the biceps muscle acting with a moment arm of 2.5 cm, what is the muscle force in that biceps muscle?

f=ma newton

f=100x2.5=250n

total distance/total time

(85 + 82)/(5+3)

167/8

20 just over

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation