Someone pls help with question 4

given.. mass of copper 2kg

from the concept

heat lost from an object=heat gained by the other object

Heat=McΔT

Mč x Cč x ΔTč = Mw x Cw x ΔTw

2kg x 385J/kg°C x (100°c - {F}) = 5kg x 4200J/kg°C x ({f} - 20°C)

77000 - 770F = 21000F - 420,000

21770F =497000

divide both sides

F=22.83°C

therefore the final temperature of the water was 22.83°C

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer