Rotation of the lever OA is controlled by the motion of the contacting circular disk of radius r = 300 mm whose center is given a horizontal velocity v = 1.64 m/s. Determine the angular velocity ω (positive if counterclockwise, negative if clockwise) of the lever OA when x = 880 mm.

The angular velocity is

5.64rad/s

Explanation:

This problem bothers on curvilinear motion

The angular velocity is defined as the rate of change of angular displacement it is expressed in rad/s

We know that the velocity v is given as

v= ωr

Where ω is the angular velocity

r is 300mm to meter = 0.3m

the radius of the circle

described by the level

v=1.64m/s

Making ω subject of the formula and solving we have

ω=v/r

ω=1.64/0.3

ω=5.46 rad/s

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this