A tennis ball (m=0.2 kg) is thrown at a brick wall. it is traveling horizontally at 18 m/s just before hitting the wall and rebounds the wall at 12 m/s, still traveling horizontally. the ball is in contact with the wall for 0.02 s. what is the magnitude of the average force of the wall on the ball

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.