You are assigned to do some calculations for a movie stunt that involves a car on a straight road. the road pictured above has a hill that rises 8.0 m above the flat region

Calculate the time it takes for the car to reach the beginning of the hill given that acceleration as already found in part a is 2.89 m/s²

5.88 s

Explanation:

Using kinematic equation, v=u+at where v and u are the final and initial velocities respectively, a is acceleration and t is time.

Considering the first part, acceleration is already found as 2.89 m/s and the final velocity is given as 17 m/s while the initial velocity is zero since it is at rest.

Making t the subject of formula then

t=(v-u)/a

Substituting the given figures then

t=(17-0)/2.89=5.8823529411764s

Rounded off, t=5.88 s

it may be wrong but i think its a

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop