A block of mass 10 kg is kept on a horizontal surface of coefficient of friction 0.1 if horizontal force of 5N acts on body then fractional force is equal to

First, I’ll like to clarify what is the question requesting the answer for? It should be either asking for the frictional force or resultant force. As such, I’ll provide solutions to solve for both problems.

Frictional force = (Co-efficient of friction) X (Normal reaction force of the object)

In the question, it is given that

Co-Efficient of friction = 0.1
Normal reaction force = Weight of the block
= mass of block X G
= (10 X 9.81)
= 98.1N

Hence, friction = (0.1 X 98.1)
= 9.81N (frictional force)

OR

However, since a horizontal force of 5N was applied, the frictional force is 9.81N, there will be a resultant force of 9.81N - 5N = 4.81N. (Resultant force)

Arise 8 run 1 this means go 8 up and 1 across, which is steepest