Physics, 22.04.2020 02:09 mooreadrian412

Cousin Throckmorton is playing with the clothesline. One end of the clothesline is attached to a vertical post. Throcky holds the other end loosely in his hand, so that the speed of waves on the clothesline is a relatively slow 0.740m/s . He finds several frequencies at which he can oscillate his end of the clothesline so that a light clothespin 43.0cm from the post doesn't move. What are these frequencies?

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Answer from: nicky123415

The obsrved frquencies are f= n (0.86) Hz n = 1,2,3,...,n.

Explanation:

From the question we are told that

The speed of the wave is v = 0.740 m/s

The distance from the post is $d = 43.0cm = \frac{43}{10} = 0.43m$

Generally frequency is mathematically represented as

$f = \frac{v}{\lambda }$

so for the first frequency which the the fundamental frequency(first harmonic frequency) the clothesline(string) would form only one loop and hence the length between the vertical post and throcky hands is mathematically represented as

$L = \frac{\lambda}{2}$

=> $\lambda = 2L$

$f_f =f_1= \frac{v}{2L}$

Substituting values

$f_f = f_1 = \frac{0.740}{2* 0.43}$

= 0.860 Hz

For the second harmonic frequency i.e is when the clothesline(string) forms two loops the length is mathematically represented as

$L = \lambda$

So the second harmonic frequency is

$f_2 = \frac{v}{L}$

$f_2 = 2 * \frac{v}{2L}$

$f_2 =\frac{0.740}{0.430}$

= 1.72Hz

For the third harmonic frequency i.e when the clothesline(string) forms three loops the length is mathematically represented as

$L = 3 * \frac{\lambda }{2}$

So the wavelength is

$\lambda = \frac{2L}{3}$

And the third harmonic frequency is mathematically evaluated as

$f_3 = \frac{v}{\frac{2L}{3} }$

$= 3 * \frac{v}{2L}$

f_3=2.58Hz

Looking at the above calculation we can conclude that the harmonic frequency of a vibrating string(clothesline) can be mathematically represented as an integer multiple of the fundamental frequency

i.e

f = n f_f

$f = n \frac{v}{2L}$

f= n (0.86) Hz

Where n denotes integer values i.e n = 1,2,3,....,n.

Note : The length that exist between two nodes which are successive is equivalent to half of the wavelength so when one loop is form the number of nodes would be 2 and on anti-node

Answer from: Quest

no. bullets are macro objects. wave nature is for light waves, extremely tiny particles. if a light particle was the size of your finger, the bullet would be the size of the universe. so basically, that huge difference in size makes the wave nature of matter insignificant.

Answer from: Quest

Answerapply an acl that has all deny ace statement;

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