Two equal-magnitude forces are applied to a door at the doorknob. The first force, F1, is applied perpendicular to the door, and the second force, F2, is applied at 25° to the plane of the door. Which force exerts the greater torque about the door hinge?

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft